Precalculus, Chapter 6, 6.3, Section 6.3, Problem 52

The magnitude of a vector u = a*i + b*j, such that:
|u| = sqrt(a^2+b^2)
Since the problem provides the magnitude |v| = 8 , yields:
8= sqrt(a^2+b^2)
The direction angle of the vector can be found using the formula, such that:
tan theta = b/a
Since the problem provides the information that the direction angle of the vector v coincides to the direction angle of vector u, yields:
tan theta= 3/3 => tan theta = 1 =>b/a = 1 => a = b
Replacing a for b in equation 8 = sqrt(a^2+b^2) yields:
8 = sqrt(a^2+a^2)=> 8 = +-a*sqrt 2 => a = +-4sqrt2
b = +-4sqrt2
Hence, the component form of the vector v can be <4sqrt2,4sqrt2> or <-4sqrt2,-4sqrt2>.

Comments

Popular posts from this blog

How does Bilbo show leadership and courage in The Hobbit?

In “Goodbye to All That,” Joan Didion writes that the “lesson” of her story is that “it is distinctly possible to remain too long at the fair.” What does she mean? How does the final section of the essay portray how she came to this understanding, her feelings about it, and the consequences of it?

Why does the poet say "all the men and women merely players"?