Beginning Algebra With Applications, Chapter 6, Test, Section Test, Problem 22
Solve by addition method:
$
\begin{equation}
\begin{aligned}
9x-2y =& 17 \\
5x+3y =& -7
\end{aligned}
\end{equation}
$
$
\begin{equation}
\begin{aligned}
3(9x-2y) =& (17)3
&& \text{Eliminate $y$: Multiply each side of equation 1 by 3 }
\\
2 (5x+3y) =& (-7)2
&& \text{and Multiply each side of equation 2 by 2}
\\
\\
27x - 6y =& 51
&&
\\
10x + 6y =& -14
&&
\\
\hline
\\
37x =& 37
&& \text{Add the equations}
\\
x =& 1
&& \text{Solve for } x
\end{aligned}
\end{equation}
$
Substitute the value of $x$ in equation 1
$
\begin{equation}
\begin{aligned}
9(1)-2y =& 17
\qquad \text{Solve for } y
\\
9-2y =& 17
\\
-2y =& 8
\\
y =& -4
\end{aligned}
\end{equation}
$
The solution is $(1,-4)$.
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