Calculus of a Single Variable, Chapter 6, 6.3, Section 6.3, Problem 13

For the given problem: yln(x)-xy'=0 , we can evaluate this by applying variable separable differential equation in which we express it in a form of f(y) dy = f(x)dx .
to able to apply direct integration: int f(y) dy = int f(x)dx .
Rearranging the problem:
yln(x)-xy'=0
yln(x)=xy' or xy' = y ln(x)
(xy')/(yx) = (y ln(x))/(yx)
(y') /y = ln(x)/x
Applying direct integration, we denote y' = (dy)/(dx) :
int (y') /y = int ln(x)/x
int 1 /y (dy)/(dx) = int ln(x)/x
int 1 /y (dy)= int ln(x)/x dx

For the left side, we apply the basic integration formula for logarithm: int (du)/u = ln|u|+C
int 1 /y (dy) = ln|y|
For the right side, we apply u-substitution by letting u= ln(x) then du = 1/x dx .
int ln(x)/x dx=int udu
Applying the Power Rule for integration : int x^n= x^(n+1)/(n+1)+C .
int udu=u^(1+1)/(1+1)+C
=u^2/2+C
Plug-in u = ln(x) in u^2/2+C , we get:
int ln(x)/x dx =(ln(x))^2/2+C
Combining the results, we get the general solution for differential equation (yln(x)-xy'=0) as:
ln|y|=(ln|x|)^2/2+C

The general solution: ln|y|=(ln|x|)^2/2+C can be expressed as:
y = C_1e^((ln|x|)^2/2)+C .

Comments

Popular posts from this blog

How does Bilbo show leadership and courage in The Hobbit?

What was the effect of World War II on African Americans?

How is Jack in William Golding's The Lord of the Flies presented as militaristic?