Beginning Algebra With Applications, Chapter 3, 3.3, Section 3.3, Problem 140

Evaluate $\displaystyle \frac{3}{8}(16 - 8c) - 9 \geq \frac{3}{5}(10c - 15) + 7$

$
\begin{equation}
\begin{aligned}
\frac{3}{8} (16) - \frac{3}{8} (8c) - 9 &\geq \frac{3}{5}(10c) - \frac{3}{5} (15) + 7 && \text{Use the Distributive Property to remove the parenthesis}\\
\\
6 - 3c - 9 &\geq 6c - 9 + 7 && \text{Simplify}\\
\\
-3c - 6c &\geq - 9 + 7 - 6 + 9 && \text{Group terms}\\
\\
-9c &\geq 1 && \text{Combine like terms}\\
\\
\frac{-9c}{-9} &\geq \frac{1}{-9} && \text{Divide each side by -9}\\
\\
c &\leq -\frac{1}{9} && \text{Remember that if you divide or multiply numbers ,the inequality symbol reverses}
\end{aligned}
\end{equation}
$

Comments

Popular posts from this blog

How does Bilbo show leadership and courage in The Hobbit?

What was the effect of World War II on African Americans?

How is Jack in William Golding's The Lord of the Flies presented as militaristic?