Single Variable Calculus, Chapter 2, 2.2, Section 2.2, Problem 33

Find $\displaystyle\lim\limits_{x \rightarrow 1^-} \frac{1}{x^3-1}$ and $\displaystyle \lim\limits_{x \rightarrow 1^+} \frac{1}{x^3-1}$


a.) By evaluating $f(x) = \displaystyle \frac{1}{x^3-1}$ for values of $x$ that approach 1 from the left and from the right.


if
$
\quad \begin{array}{cc}
x^- =& 0.99999 \qquad \displaystyle f(x) =& \frac{1}{(0.99999)^3-1} \qquad &=& -33333.67\\
x^+ =& 1.00001 \qquad \displaystyle f(x) =& \frac{1}{(1.00001)^3-1} \qquad &=& 33333
\end{array}
$



b.) By reasoning:



$\displaystyle \lim\limits_{x \rightarrow 1^-} \frac{1}{x^3-1}$ if $x$ is close to 1 but smaller than 1, the denominator is a very small
negative number. Therefore the quotient is a very large negative number.



$\displaystyle \lim\limits_{x \rightarrow 1^+} \frac{1}{x^3-1}$ if $x$ is close to 1 but larger than, the denominator is a very small
positive number. Therefore the quotient is a very large positive number.




c.) By graphing:







The graph shows that as $x$ approaches 1 from the right, the value of the limit approaches $\infty$. On the other hand, as $x$ approaches
1 from the left, the value of the limit approaches $-\infty$

Comments

Popular posts from this blog

How does Bilbo show leadership and courage in The Hobbit?

What was the effect of World War II on African Americans?

How is Jack in William Golding's The Lord of the Flies presented as militaristic?