int sec^5x tan^3x dx Find the indefinite integral

intsec^5(x)tan^3(x)dx
Let's rewrite the integral as:
intsec^5(x)tan^3(x)dx=intsec^5(x)tan^2(x)tan(x)dx
Now using the trigonometric identity:tan^2(x)=sec^2(x)-1
=intsec^5(x)(sec^2(x)-1)tan(x)dx
=intsec^4(x)(sec^2(x)-1)sec(x)tan(x)dx
Now apply the integral substitution:u=sec(x)
du=sec(x)tan(x)dx
=intu^4(u^2-1)du
=int(u^6-u^4)du
apply the sum rule,
=intu^6du-intu^4du
=(u^(6+1)/(6+1))-(u^(4+1)/(4+1))
=u^7/7-u^5/5
substitute back u=sec(x) and add a constant C to the solution,
=(sec^7(x))/7-(sec^5(x))/5+C

Comments

Popular posts from this blog

How does Bilbo show leadership and courage in The Hobbit?

In “Goodbye to All That,” Joan Didion writes that the “lesson” of her story is that “it is distinctly possible to remain too long at the fair.” What does she mean? How does the final section of the essay portray how she came to this understanding, her feelings about it, and the consequences of it?

Why does the poet say "all the men and women merely players"?