Precalculus, Chapter 1, 1.2, Section 1.2, Problem 64
Find the intercepts of the equation $y = x^4 - 1$ and test for symmetry.
$x$-intercepts:
$
\begin{equation}
\begin{aligned}
y =& x^4 - 1
&& \text{Given equation}
\\
0 =& x^4 - 1
&& \text{To find the $x$-intercept, we let } y = 0
\\
1 =& x^4
&&
\\
\pm 1 =& x
&&
\end{aligned}
\end{equation}
$
The $x$-intercepts are $(-1,0)$ and $(1,0)$
$y$-intercepts:
$
\begin{equation}
\begin{aligned}
y =& x^4 - 1
&& \text{Given equation}
\\
y =& (0)^4 - 1
&& \text{To find the $y$-intercept, we let } x = 0
\\
y =& -1
&&
\end{aligned}
\end{equation}
$
The $y$-intercept is $(0,-1)$
Test for symmetry
$x$-axis:
$
\begin{equation}
\begin{aligned}
y =& x^4 - 1
&& \text{Given equation}
\\
-y =& x^4 - 1
&& \text{To test for $x$-axis symmetry, replace $y$ by $-y$ and see if the equation is still the same}
\end{aligned}
\end{equation}
$
The equation changes so it is not symmetric to the $x$-axis
$y$-axis:
$
\begin{equation}
\begin{aligned}
y =& x^4 - 1
&& \text{Given equation}
\\
y =& (-x)^4 - 1
&& \text{To test for $y$-axis symmetry, replace$ x$ by $-x$ and see if the equation is still the same}
\\
y =& x^4 - 1
&&
\end{aligned}
\end{equation}
$
The equation is still the same so it is symmetric to the $y$-axis
Origin:
$
\begin{equation}
\begin{aligned}
y =& x^4 - 1
&& \text{Given equation}
\\
-y =& (-x)^4 - 1
&& \text{To test for origin symmetry, replace both $x$ by $-x$ and y by $-y$ and see if the equation is still the same}
\\
-y =& x^4 - 1
&&
\end{aligned}
\end{equation}
$
The equation changes so it is not symmetric to the origin.
Therefore, the equation $y = x^4 - 1$ has an intercepts $(-1,0), (1,0)$ and $(0,-1)$ and it is symmetric to the $y$-axis.
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