Question is: a car travelling at 140 km/h decelerates for 20 secs. During this time it travels 500 m. What is its deceleration? What is its speed after deceleration?

Hello!
As I understand, the deceleration is uniform (the same all the time). Denote it as agt0 and denote the initial speed as V_0.  In m/s V_0 = 140/3.6.
Then the speed is V(t) = V_0 - a*t  (note the minus sign), and the displacement is D(t) = V_0 t - (a t^2)/2.
It is given that D(20) = 500, therefore V_0 * 20 - (a * 20^2)/2 = 500. From this we find  a = 2*(140/3.6*20-500) / 20^2 approx1.39 (m/s^2).
Then we can find the speed after deceleration: it is
V(20) = V_0 - a*20 approx 140/3.6 - 20*1.39 approx 11.1 (m/s).
The value is positive which means the direction of movement remains the same.
The answers: the deceleration is about 1.39 m/s^2, and the final speed is about 11.1 m/s.
 

Comments

Popular posts from this blog

How does Bilbo show leadership and courage in The Hobbit?

In “Goodbye to All That,” Joan Didion writes that the “lesson” of her story is that “it is distinctly possible to remain too long at the fair.” What does she mean? How does the final section of the essay portray how she came to this understanding, her feelings about it, and the consequences of it?

Why does the poet say "all the men and women merely players"?