y = x^2(2+e^x) Determine whether the function is a solution of the differential equation xy' - 2y = x^3e^x

To determine whether the given function is a solution of the given differential equation, we first need to find the derivative of the function.
y'=2x(2+e^x)+x^2e^x
Now we plug that into the equation.
x[2x(2+e^x)+x^2e^x]-2x^2(2+e^x)=
2x^2(2+e^x)+x^3e^x-2x^2(2+e^x)=
x^3e^x  
As we can see, after simplifying the left hand side we get the right hand side of the equation. This means that the given function is a solution of the given differential equation.
Of course, this is only one of  the solutions. The general solution of this equation is y=x^2(c+e^x).
The image below shows graphs of several such functions for different values of c. The graph of the function from the beginning is the green one.                                                                     
https://en.wikipedia.org/wiki/Ordinary_differential_equation

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