Calculus of a Single Variable, Chapter 3, 3.3, Section 3.3, Problem 36

Given: f(x)=(x^2-2x+1)/(x+1)
Find the critical numbers by setting the first derivative equal to zero and solving for the x value(s).
f'(x)=[(x+1)(2x-2)-(x^2-2x+1)(1)]/(x+1)^2=0
2x^2-2x+2x-2-x^2+2x-1=0
x^2+2x-3=0
(x+3)(x-1)=0
x=-3,x=1
The critical numbers are x=-3 and x=1. Critical numbers also exist where f(x) is not defined. Therefore x=-1 is also a critical number.
If f'(x)>0 the function is increasing on the interval.
If f'(x)<0 the function is decreasing on the interval.
Choose an x value that is less than -3.
f'(-4)=.5556 Since f'(-4)>0 the function is increasing in the interval
(-oo,-3).
Choose an x value that is between -3 and -1.
f'(-2)=-3 Since f'(-2) >0 the function is decreasing in the interval (-3, -1).
Choose an x value that is between -1 and 1.
f'(0)=-3 Since f'(0)<0 the function is decreasing in the interval (-1, 1).
Choose an x value that is greater than 1.
f(2)=.5556 since f'(2)>0 the function is increasing in the interval (1, oo).
Since the function changed direction from increasing to decreasing there is a relative maximum at x=-3. The relative maximum is at the point (-3, -8).
Since the function changed direction form decreasing to increasing there is a relative minimum at x=1. The relative minimum is at the point (1, 0).

Comments

Popular posts from this blog

How does Bilbo show leadership and courage in The Hobbit?

In “Goodbye to All That,” Joan Didion writes that the “lesson” of her story is that “it is distinctly possible to remain too long at the fair.” What does she mean? How does the final section of the essay portray how she came to this understanding, her feelings about it, and the consequences of it?

Why does the poet say "all the men and women merely players"?