Intermediate Algebra, Chapter 3, 3.4, Section 3.4, Problem 8
Illustrate the linear inequality $x + y \leq -3$ in two variables.
To graph $x + y \leq -3$ we must graph the boundary line $x + y = -3$ first. To do this, we need to find the
intercepts of the line
$x$-intercept (set $y = 0$):
$
\begin{equation}
\begin{aligned}
x + 0 &= - 3\\
\\
x &= -3
\end{aligned}
\end{equation}
$
$y$-intercept (set $x = 0$):
$
\begin{equation}
\begin{aligned}
0 + y &= - 3\\
\\
y &= - 3
\end{aligned}
\end{equation}
$
Now, by using test point. Let's say point $(-4,-2)$ from the left of the boundary line.
$
\begin{equation}
\begin{aligned}
x + y &\leq - 3\\
\\
-4 + (-2) &\leq -3 \\
\\
-4 - 2 &\leq -3\\
\\
-6 &\leq -3
\end{aligned}
\end{equation}
$
Since the inequality symbol is $\leq$, then the boundary line must be solid.
Moreover, since the test point satisfy the inequality, then we must shade the left
portion of the boundary line. So the graph is,
Comments
Post a Comment