Beginning Algebra With Applications, Chapter 5, 5.3, Section 5.3, Problem 56

Graph $\displaystyle y = 5x - 2$ by using the slope and $y$-intercept.

$y$-intercept:


$
\begin{equation}
\begin{aligned}

y =& 5x - 2
&& \text{Given equation}
\\
y =& 5(0) - 2
&& \text{To find the $y$-intercept, let } x = 0
\\
y =& -2
&&
\end{aligned}
\end{equation}
$


The $y$-intercept is $(0,-2)$


$
\begin{equation}
\begin{aligned}

m =& \frac{\text{change in } y}{\text{change in } x}
\\
\\
m =& \frac{5}{1}
\\
\\
m =& 5

\end{aligned}
\end{equation}
$


Beginning at the $y$-intercept, move to the right 1 unit and then up 5 units.







$(1, 3)$ are the coordinates of a second point on the graph.

Draw a line through $(0,-2)$ and $(1, 3)$

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