Precalculus, Chapter 3, 3.1, Section 3.1, Problem 54

Since you already have the same bases, set the exponents equal to each other.
x^(2)+6=5x
Subtract 5x from both sides
x^(2)-5x+6=0
Factor the quadratic function
(x-2)(x-3)=0
Set each term equal to 0
x-2=0 and x-3=0
Solve each equation for x
x=2 and x=3

Comments

Popular posts from this blog

Calculus: Early Transcendentals, Chapter 9, 9.3, Section 9.3, Problem 18

In what ways might RFID technology be used to serve customers better? What problems might arise? Do you think that the technology might be valuable when implanted in animals or people?

Single Variable Calculus, Chapter 7, 7.4-2, Section 7.4-2, Problem 52